0.02 °C = 273.17 K. Formula: K = °C + 273.15, so 0.02 + 273.15 = 273.17 K.
How to convert Degrees Celsius to Degrees Kelvin
K = °C + 273.15
- Start with 0.02 °C.
- Apply the formula: 0.02 + 273.15 = 273.17.
- Answer: 0.02 °C = 273.17 K.
Degrees Celsius to Degrees Kelvin table
| Degrees Celsius (°C) | Degrees Kelvin (K) |
|---|---|
| 0.01 °C | 273.16 K |
| 0.02 °C | 273.17 K |
| 0.03 °C | 273.18 K |
| 0.04 °C | 273.19 K |
| 0.05 °C | 273.2 K |
| 0.06 °C | 273.21 K |
| 0.07 °C | 273.22 K |
| 0.08 °C | 273.23 K |
| 0.09 °C | 273.24 K |
| 0.1 °C | 273.25 K |
| 0.11 °C | 273.26 K |
| °C | K |
|---|---|
| 1 °C | 274.15 K |
| 5 °C | 278.15 K |
| 10 °C | 283.15 K |
| 50 °C | 323.15 K |
| 100 °C | 373.15 K |
| 1,000 °C | 1,273.15 K |
Good to know
°F = °C × 9/5 + 32 and °C = (°F − 32) × 5/9. K = °C + 273.15.
Water freezes at 0 °C (32 °F) and boils at 100 °C (212 °F) at sea level.